Parsing Json in Java using JsonParser

You can use one of the many available Json Parser for the purpose. I have personally used following in simple applications. You can refer this tutorial:

 

import org.json.simple.JSONArray;

import org.json.simple.JSONObject;

import org.json.simple.parser.JSONParser;

import org.json.simple.parser.ParseException;

 

You might need to install dependencies first:

In case you are on maven, use following to set a proper environment for the compiler, in order to recognize the JSON's classes. If you want to built your project via Maven, you should add the following dependency to your pom.xml:

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<dependency>     <groupId>com.googlecode.json-simple</groupId>     <artifactId>json-simple</artifactId>     <version>1.1</version> </dependency>

Otherwise, you have to add the newest version of json-simple-1.1.1.jar in your CLASSPATH.

First you need to Declare an instance of the JSONParser:

 JSONParser parse = new JSONParser(); 

Then, Convert the string objects into JSON objects:

 JSONObject jobject = (JSONObject)parse.parse(inline); 

If you view the JSON structure, it will be something like this:

{

   "results" : [

      {

   "place_id" : "aa1123",

         "types" : [ "locality", "book" ]

      } ]

}

Then you can convert the JSON object into JSONArray 

JSONArray jsonarray = (JSONArray) jobj.get(“results”); 

Now you can use as per your need, for eg.

get the elements within the results array. Here is how you do it:

//Get data for Results array

for(int i=0;i<jsonarray.size();i++)

{

//Store the JSON objects in an array

//Get the index of the JSON object and print the values as per the index

JSONObject jsonobj_1 = (JSONObject)jsonarray.get(i);

System.out.println(“Elements under results array”);

}